Friday 27 January 2017

Jobs in Animal Husbandry Department, Udhampur, J&K

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Applications on prescribed format are invited from the permanent residents of District Udhampur for recruitment to Class-IV posts (Attendants) in Animal Husbandry Department Udhampur (District cadre) under special recruitment rules notified vide SRO-202 OF 2015 dated: 30-06-2015 However, for Class-IV posts reserved under Scheduled Caste Category. The candidate from any district of Jammu and Kashmir belonging to Scheduled Caste category can also apply.

Pay Scale:  pay Band of 4440-7440+GP of Rs 1300/-
Last Date: 21-Feburary-2017 from 10 AM to 4 PM

Tuesday 24 January 2017

Quantitative Aptitude questions for IBPS, UPSC, CAT and other national exams

With 2 comments:
Quantitative aptitude questions and solutions for preparation for practice for various exams in 2017 are given below. Try to solve the questions on your own. If you are unable to solve the solution after many attempts, only then look for the solutions. Solutions to the problem are given at the end.

Directions for Questions 1 to 10: Read the following and answer the questions that follow.
A fort contains a granary, that has 1000 tons of grain. The fort is under a siege from an enemy army
that has blocked off all the supply routes.
The army in the fort has three kinds of soldiers:
Sepoys --> 2,00,000.
Mantris --> 1,00,000
Footies --> 1,00,000
100 Sepoys can hold 5% of the enemy for one month.
100 Mantris can hold 10% of the enemy for 15 days.
50 Footies can hold 5% of the enemy for one month.
A sepoy eats 1 kg of food per month, a Mantri eats 0.5 kg of food per month and a footie eats 3 kg of food. (Assume 1 ton = 1000 kg).
The king has to make some decisions based on the longest possible resistance that can be offered to the enemy.
If a king selects a soldier, he will have to feed him for the entire period of the resistance. The king is not obliged to feed a soldier not selected for the resistance.
(Assume that the entire food allocated to a particular soldier for the estimated length of the resistance is redistributed into the king’s palace in case a soldier dies and is not available for the other soldiers.)

1. If the king wants to maximise the time for which his resistance holds up, he should
(a) Select all mantris 
(b) Select all footies
(c) Select all sepoys 
(d) None of these

2. Based on existing resources, the maximum number of months for which the fort’s resistance
can last is
(a) 5 months 
(b) 20 months
(c) 7.5 months 
(d) Cannot be determined

3. If the king makes a decision error, the maximum reduction in the time of resistance could be
(a) 15 months 
(b) 12.5 months
(c) 16.66 months 
(d) Cannot be determined

4. If the king estimates that the attackers can last for only 50 months, what should the king do to ensure victory?
(a) Select all mantris
(b) Select the mantris and the sepoys
(c) Select the footies
(d) The king cannot achieve this

5. If a reduction in the ration allocation by 10% reduces the capacity of any soldier to hold off the enemy by 10%, the number of whole months by which the king can increase the life of the resistance by reducing the ration allocation by 10% is
(a) 4 months 
(b) 2 months
(c) No change 
(d) This will reduce the time

6. The minimum amount of grain that should be available in the granary to ensure that the fort is not lost (assuming the estimate of the king of 50 months being the duration for which the enemy can last is correct) is
(a) 2000 tons 
(b) 2500 tons
(c) 5000 tons 
(d) Cannot be determined

7. If the king made the worst possible selection of his soldiers to offer the resistance, the percentage increase in the minimum amount of grain that should be available in the granary to ensure that the fort is not lost is 
(a) 100%
(b) 500% 
(c) 600%
(d) Cannot be determined 

8.The difference in the minimum grain required for the second worst choice and the worst choice to ensure that the resistance lasts for 50 months is 
(a) 5000 tons
(b) 7500 tons 
(c) 10000 tons
(d) Cannot be determined

9.If the king strategically attacks the feeder line on the first day of the resistance so that the grain is no longer a constraint, the maximum time for which the resistance can last is 
(a) 100 months
(b) 150 months 
(c) 250 months
(d) Cannot be determined 

10.If the feeder line is opened after 6 months and prior to that the king had made decisions based on food availability being a constraint then the number of months (maximum) for which the resistance could last is 
(a) 100 months
(b) 150 months 
(c) 5 months
(d) Cannot be determined

11. Three friends A, B and C start from P to Q that are 100 km apart. A is on a moped while B is riding pillion and C walks on. A takes B to a point R and returns to pick up C on the way and
takes him to point Q. B, on the other hand, walks to Q from point R (R is the mid-point
between P and Q).
If the ratio of speeds of the three people is 5 : 2 : 2, find where will the last person be when the first person reaches Q.
(a) 12.85 km from Q 
(b) 12.75 km from Q
(c) 16.66 km from Q 
(d) 83.33 km from P

12.In his book on Leonardo da Vinci, Sigmund Freud, after a detailed psychoanalysis concluded that Goethe could complete the masterpiece in nine days as he could channelize overly but was more possessed as a result of which he could generate 50% more efficiency than Goethe. The number of days it takes Leonardo da Vinci to do the same piece of work that Goethe completes in nine days is:
(a) 4 (1/2) days
(b) 6 days
(c) 13 (1/2) days
(d) None of these

13.A dealer buys oil at Rs. 100, Rs. 80 and Rs.60 per liter. He mixes them in the ratio 5:6:7 by weight and sells them at a profit of 50%. At what price does he sell oil?
(a) Rs. 80/liter
(b) Rs.116.666/ liter
(c) Rs. 95/liter
(d) None of these

14. The figure contains three squares with areas of 100 m2, 49 m2, and 16 m2 lying side by side. Rahim wishes to reduce the length AB to 19 m by reducing area of only one of the squares without altering its shape, what is the maximum reduction (in %) in the area of that square?

Quantitative Aptitude questions for IBPS, UPSC and other national exams

(a) (Approx) 33%
(b) 50%
(c) (Approx) 66%
(d) 75%

15. The village of Hara Kiri has two-thirds of its male population married to 90% of its women population. Each of such man is married to exactly two of such women. What is the minimum possible 4 digit population of the village (Children are not counted as part of the populationunless they are married)?
(a) 1005
(b) 1026
(c) 1080
(d) Cannot be determined/None of these

Answers and Solutions to problems above: 
Sol 1. If all sepoys are chosen, the food requirement will be 200 tons/month. The resistance will last for 1000/200 = 5 months.
If footies are chosen, the food will last for 1000/100×3 = 3.33 months.
If mantris are chosen, the food will last for 1000/100×0.5 = 20 months
So, answer is (a)

Sol 2. B) 20 months

Sol 3. c) 20-3.33 = 16.66 months

Sol 4. d) The king cannot achieve this based on existing resources

Sol 5. No change will occur

Sol 6. for 50 months, mantris will require 1000×2.5/100 ×0.5 = 50 months
Mantris eat 50 tons of food per month. If 2500 tons of food is available only then mantris can last for 50 months. Sepoys and footies eat more food than Mantris so minimum amount required is 2500 tons

Sol 7. The worst decision will occur for footies
For footie , 1000×15/100×3 = 50 months
So, 15000 tons required for footies
% increase from the minimum amount= (15000 - 2500)/2500 = 5 ×100 = 500%

Sol 8. In worst case the minimum grain required is 15000 tons and the 2nd worst case occurs for soldiers where the minimum grain required is 10000 tons for 50 months.
So, the difference is 15000-10000 = 5000 tons

Sol 9. For questions 19 & 20, when food is not a constraint, the number of lives become constraint. 
So, to offer 100% resistance
for sepoys, 100  sepoys offer 5%
so, 20×100 sepoys offer 100% resistance
Similarly 1000 mantris offer 100% resistance for 15 days 
Or 2000 mantris offer 100% resistance for 1 month
& 50 footies offer 5% resistance for 1 month 
1000 footies offer 100% resistance for 1 month
So, length of resistance = 200000/2000 + 100000/2000 + 100000/1000 = 250 months

Sol 10. If decision based on food are made before 6 months, then all the sepoys and footies will die in 5 months as the maximum period for survival of sepoys is 5 months. After 6th month, when feeder line is opened food no longer is a constraint so resistance becomes constraint.
Number of mantris that will die in 6 months are  2000×6 = 12000 mantris will be lost.

Sol 11. the question may look lengthy or confusing but the solution is easy if you tske a step by step approach. Let's solve the problem:
let the speeds of A,B and C be 5, 2 and 2 km/hr
I. A and B goes from P to R. PR = 50km
T(A+B) = 50/5 =10
In the same time C covers a distance = 2×10 =20

II. now A returns from R to pick C and C moves ahead of 20 to meet eachother.
SO, time taken by C ahead of 20 km to meet A = time taken by A from R to meeting point,S 
time = x/2 = (30 - x)/5 => x = 60/7
time taken by C  = 60/7×2 = 30/7
SO total distance covered by C to point S = 20+60/7 =200/7

distance covered by B in the same time= 30×2/7 =60/7
distance covered by B = 50+60/7 =410/7
III. after the point of meeting of C and A, both move towards Q at speed 5 km/hr.
SO distance that needs to be covered by C and A is 100 - 200/7 = 500/7
and this distance is covered in 500/7×5 =100/7 hrs

Distance that needs to be covered by B is 100 - 410/7 = 290/7
And this distance is covered by B in 290/7×2 = 145/7 hrs

SO, C and A reach point Q earlier than B. SO, distance that needs to be covered by B to reach point Q is (145-100)×2/7 = 90/7 = 12.85km. SO B is at a distance of 12.85 km from Q when A and C reach Q.

Sol 12. Since efficiency is 50% more. 
Efficiency of leonardo da vanci =1.5 times the efficiency of goathe 
So, the number of days to do the same work =9/1.5 days = 6 days

Sol 13. Price of the mixed oil =
5/18 X 100 + 6/18 X 80 + 7/18 X 60
= 1400/18 = 77.777
Now he sells at a profit of 50%
Therefore , selling price = 77.77 x 1.5 = 116.66

Sol 14. The given squares have lengths of 10, 7 and 4. The sum of lengths =10+7+4=21
Now we have to reduce 2 m from side of one of the squares so that the total length becomes equal to 19. But the length must be reduced from that square for which the reduction in area is maximum. This Will happen when the length is reduced from smallest square . so (4^2 -2^2) = 4^2 =12/16 =3/4 which corresponds to 75% reduction in area .

Sol 15. Let us write the conditions given:
Married Male(mm) = 2/3 x total male 
Total Female x 0.9 =married female (MF)

Total population = total male + total Female 
= 3/2 x married Male + MF/0.9
= 3/2 x married Male + 2/0.9 x MF 
= 67/18 x married Male
So, mM = 18/67 x total population 
Now try the values in options . The smallest 4 digit value that results in natural number is 1005

Thursday 19 January 2017


With No comments:
UPSC invites applications for National Defence Academy and Naval Academy Examination 2017. The candidates applying for the examination should ensure that they fulfil all the eligibility conditions for admission to the Examination.


Wednesday 18 January 2017

New free internet 4G Plans for 2017

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After Reliance Jio's free 4G offer, a war has been started between telecom giants to provide cheaper 4G plans for enticing new users. Reliance claimed Jio's users to be more than 75 million plus by ending December 2016. Now other Telcos have decided to take the bull by horn by offering attractive offers in 2017.

New free internet 4G Plans for 2017

Tuesday 17 January 2017

IBPS Exam Calendar for 2017

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IBPS has released the exam schedule for the year 2017. The exam will start from the month of September 2017. More updates will be provided abut the exams in the future. The original notification has been reproduced below. For original notification, follow the link at the end.

IBPS Exam Calendar for 2017

Thursday 5 January 2017

Jobs in Jammu University for teaching Posts

With No comments:
Applications complete in all respects are invited by Jammu University, on prescribed form are invited for the following posts so as to reach the undersigned 

Jobs in Jammu University for teaching Posts

Last Date:  31st January, 2017

Total Vacancy: 99 posts

Wednesday 4 January 2017

JKPSC Jobs for District Litigation Officer

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Applications through online mode are invited from the permanent residents of Jammu & Kashmir State possessing the prescribed academic/professional qualifications and age for the posts of District Litigation Officer of the State as per the category-wise break-up tabulated below: -

JKPSC Jobs for District Litigation Officer

Tuesday 3 January 2017

Jobs in J&K Police for the post of Sub-Inspector (Executive/ Armed) - 686 posts

With No comments:
Applications online are invited from the permanent residents of J&K State for their recruitment as Sub-Inspector in (Executive/Armed)Wings of J&K Police against the vacancies as per following breakup in accordance with the conditions of employment as prescribed under J&K Special Recruitment Rule 2015 notified vide SRO-202 dated 30-06-2015:-

Jobs in J&K Police for the post of Sub-Inspector (Executive/ Armed) - 686 posts
Jobs in J&K Police for the post of Sub-Inspector (Executive/ Armed) - 686 posts

Jobs for the post of Sub-Inspector in J&K Police

With No comments:
Applications online are invited from the permanent residents of J&K State for their recruitment as Sub-Inspector in (Executive/Armed)Wings of J&K Police against the vacancies as per following breakup in accordance with the conditions of employment as prescribed under J&K Special Recruitment Rule 2015 notified vide SRO-202 dated 30-06-2015:-

Jobs in J&K Police for the post of Sub-Inspector (Executive/ Armed) - 686 posts
Jobs in J&K Police for the post of Sub-Inspector (Executive/ Armed) - 686 posts

Pay scale: Rs.9300-34800+(4240/= Grade pay) 

Total Vacancy: 658 posts

Category-wise break-up of posts
Social Caste

Note:- The recruitment will be for a total number of 658 vacancies i.e. (Executive Police = 482 & Armed Police = 176).

Last Date of online application: 16th February, 2017
Last Date of Submission of Fee through Bank Challan: 20th February, 2017

Educational Qualification: The educational qualification, age and physical standards prescribed for the above mentioned posts are specified as under:-

Graduate, in any discipline, from a recognized University.
The candidate must be within the age group of 18­28 years as on 1st day of January 2016.
(The candidates born before 01.01.1988 and after 31.12.1997 shall not be eligible.) However, in­service police personnel, upto the upper age limit of 30 years.
Physical Standards
For male candidates
Height = 5’-6”(min.)
Chest = 32”(un-expanded)
For female candidates Height = 5’-2”(min.)
(However, for male candidates belonging to Leh/Kargil districts and Gorkha community, the minimum height shall be 5 ’-4 ” while for females the same shall be 5’)

Persons already in Government service and conforming to the above eligibility standards can also apply with NOC from their respective Head of the Department. The fact of any candidate being in Govt. service and having applied without NOC, if ascertained at a later stage, will deny him/her the offer of appointment.

- The candidates possessing basic eligibility criteria viz age and education qualification as prescribed here in above shall be subjected to the following tests:-

Physical Endurance Test(PET)-qualifying nature (only candidates who qualify the Physical Endurance Test (PET) shall be eligible for the PST
For Male candidates
Long Race = 1600 meters in 6/ minutes
(Six minutes thirty seconds) Pushups = 20
(one cycle of up and down to be counted as one)
For Female candidates
1000 meters in 6/ minutes (Six minutes thirty seconds)
Shot Put (4Kgs) = 14 / feet in three attempts The test shall be qualifying in nature and no marks are allotted for these tests.
Physical Standard Test (PST)
·         Measurement of Height and Chest
The candidates are also required to carry their
original documents for scrutiny during the PST
Written Examination (Objective type)
Only for the candidates who qualify the physical endurance & physical standard test and meet the required standards as at (A & B) above, respectively.
The Question paper will be of 85 marks (multiple choice) of two hours duration based on OMR sheets. The Questions will be of Graduation standard.
Viva-Voce/Personality Assessment test.
(Only for those candidates who qualify the written test)
The test will be of 15 marks.
Note:- On the basis of merit obtained in the written examination, the candidates will be called for viva voce- cum-Personality Assessment Test which shall be restricted three times the number of posts/vacancies advertised.

Application Fee: Rs. 300/-(Rupees Three Hundred only) or use the services of Common Service Centers.

The candidates shall clearly state their preference for Executive/ Armed wing at the time of filing their online application. This preference-cum-merit obtained in the selection process by the applicant shall form the basis of allocation of Executive/ Armed wing to the applicants at the time of final selection

Instructions and procedure for online submission of Application Form:
1. Please read the instructions, procedure and information carefully before you start filling the Application Form.
2. Please ensure your eligibility as per the criteria laid down in the advertisement notice.
3. Candidate is allowed to submit only one Application Form. Multiple Applications from a candidate are liable to be rejected.
4. Simple steps to be followed to apply online
1. Candidate may also visit any of the CSC (Common Service Centers) to get their Application Forms filled or else follow the procedure mentioned below.
2. The candidate have to visit
3. Fill the online Application form after clicking proceed at the bottom of the page, The candidate should supply all the details while filling the online Application Form. After successful submission of the data, Application number will be generated and it will be used for all future correspondence.
4. Upload Scanned Images of Photograph, and Signature.
-Photograph image must mention the date in which it is taken.
- The Scanned images of photograph, Signature and thumb impression should be in jpg/jpeg format only.
- Size of photograph image must be greater than 20 kb and less than 50 kb.
- Size of the signature and thumb impression image must be greater than 10kb and less than 50 kb. 
- Dimension of photograph image should be 3.5 cm (width) x 4.5 cm (height) only.
- Dimension of signature image should be 3.5 cm (length) x 1.5 cm (height) only.
5. Examination fee may be submitted through online mode or e-challan account 0747010100000005 of J&K Bank or through CSC (Common Service Centers).
Candidate is required to select the payment mode:
- Payment by Bank e-challan: After online form submission, the candidate has to click on Print challan. As soon as he/she selects, an e-challan will be generated. The candidate has to take a printout of the same and take it to the nearest branch of the J&K Bank for making payment a day after the submission of application form.
- Payment through CSC: After online form submission, candidate is required to visit any CSC for fee submission; candidate must carry his Application No. against which payment is to be made.
- Fee will be accepted through Bank challan upto a maximum of two days after
the cutoff date for filling the online application Form, failing which application is liable for rejection.
6. A service charge of Rs. 10/- per transaction inclusive of all taxes will be charged by J&K Bank.
7. However, CSC will be charge as under depending upon the nature of service required:-
a. Filling of online application Form/printout of Form = Rs. 30/-
b. Scanning/taking of photographs, signatures for uploading while filling up of online application form = Rs. 10/-
c. E-Admit card (printout) = Rs. 5/-
d. Deposit of application fee through CSC = Rs. 10/-